Math, asked by arjun238, 1 year ago

if a+b+c=0 then the value of a^2+b^2+c^2/ab+bc+ca

Answers

Answered by jainmiley1234
1
a+b+c=0
using the identity,
(a+b+c)²=a²+b²+c²+2(ab+bc+ca)
putting the value of a+b+c
0=a²+b²+c²+2(ab+bc+ca)
-2(ab+bc+ca)=a²+b²+c²
a²+b²+c²/ab+bc+ca=  -2


arjun238: nice
jainmiley1234: thanks
arjun238: the no. of zeores at the end of 100 factorial
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