if a+b+c=0 then the value of a^2+b^2+c^2/ab+bc+ca
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a+b+c=0
using the identity,
(a+b+c)²=a²+b²+c²+2(ab+bc+ca)
putting the value of a+b+c
0=a²+b²+c²+2(ab+bc+ca)
-2(ab+bc+ca)=a²+b²+c²
a²+b²+c²/ab+bc+ca= -2
using the identity,
(a+b+c)²=a²+b²+c²+2(ab+bc+ca)
putting the value of a+b+c
0=a²+b²+c²+2(ab+bc+ca)
-2(ab+bc+ca)=a²+b²+c²
a²+b²+c²/ab+bc+ca= -2
arjun238:
nice
thanks
the no. of zeores at the end of 100 factorial
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