If a + b + c = 0, then the value of a^2+b^2+c^2/
(bc + ca + ab)
is
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Answer:
-2
Step-by-step explanation:
(a+b+c)^2=(0)^2
a^2+b^2+c^2+2 (ab+bc+ca)=0
a^2+b^2+c^2=(-2 (ab+bc+ca))
Therefore (a^2+b^2+c^2)/(ab+bc+ca)=(-2)
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