if m= tan Theta + sin theta n=tan theta - sin theta prove that (m²-n²)²=16mn
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Answer:
Here we will simply both sides L.H.S and R.H.S by putting the value of m and n.
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Tan θ + sinθ = m Squaring on both sides& Tan θ - Sin θ = n Squaring on both sides we get
prove that (m² - n²)²=16mn
Tan² θ + sin² θ + 2 Tan θ sinθ = m³ ---------(1)
Tan² θ + sin² θ - 2 Tan θ sinθ = n² --------(2)
Substract (2) from (1) we get,
m² - n² = 4 Tanθ sinθ = 4 √( Tan²θ sin²θ)
= 4 √( Sin²θ /Cos²θ ( 1 - Cos²θ) )
= 4 √( Tan²θ - sin²θ)
= 4 √( Tan θ + Sin θ)(Tan θ - Sin θ )
= m2 - n2 = 4√mn ( on squaring both sides)
= (m2-n2)²=16mn
Step-by-step explanation:
hope it's helpful,,
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