Question

If a + b + c = 0, then what is the value of ^2+^2 + ^2?​

Answer 1

Answer:

If x = a, then f(a) = 0 + (a - b) + (a - c) = (a - b) + (a - c).

If x = b, then f(b) = -(b - a) + 0 + (b - c) = a - c.

If x = c, then f(c) = -(c - a) + [-(c - b)] + 0 = (a - c) + (b - c).

We see that choice A is f(a), choice B is f(c) and choice D is f(b). Furthermore, we see that both f(a) and f(c) are greater than f(b) because they both have a positive term besides a - c. Since both choices C and E are also greater than a - c, we see that f(b) = a - c must be the minimum value of f(x).

Step-by-step explanation:

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