if a negligible is small current is passed through a wire of length 15 metre and of resistance 5 ohm having uniform cross section of 6 into 10 raise to minus 7 square then can coefficient of resistivity of material is
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Answer:
Length of the wire, l =15 m
Area of cross-section of the wire, a = 6.0 × 10 - 7 m2
Resistance of the material of the wire, R = 5.0 Ω
Resistivity of the material of the wire = ÃÂ
Resistance is related with the resistivity as
Therefore, the resistivity of the material is 2 × 10 - 7 Ω
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Q]___?
=> 2× 10^-7
Explanation:
Resistance of a given conducting wire is given by
R =ρ 1 /A
where ρ is the specific resistance of the material of the conductor.
Here,
l = 15m
A= 6× 10^-7 m^2
R= 5 Ω, ρ = ?
ρ = RA / I
ρ = ( 5 × 6 × 10^-7 ) / 15
ρ = 2 × 10^-7 Ω-m
∴ The coefficient of resistivity of material is 2 × 10^-7 Ω-m !
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