Question

If a + b + c = 0, then what is the value of (a + b - c)^3
+(c + a - b)^3 + (b + c - a)^3 ?
​

Answer 1

Answer:

3(a+b-c)(c+a-b)(b+c-a)

Answer 2

Answer:

$\huge \underline \mathfrak{ \orange{answer}}$

Then,

a + b + c = 0

a + b = - c -- (I)

(a + b)^3 = (- c)^3

a^3 + b^3 + 3ab (a + b) = - c^3

from equation (I) a + b = - c

a^3 + b^3 + 3ab (- c) = - c^3

a^3 + b^3 - 3abc = - c^3

a^3 + b^3 + c^3 = 3abc

Hence,

a^3 + b^3 + c^3 ‘not equal’ 0

but,

a^3 + b^3 + c^3 ‘equal’ 3abc

Step-by-step explanation:

Hope I help you!!!