Question

If A+B+C=0,what is the value for A^2+B^2+AB

Answer 1

Answer:

c^2-ab

Step-by-step explanation:

a+b+c=0

a+b= -c

Squaring on b/s

(a+b)^2= (-c)^2

a^2+2ab+b^2=c^2

=> a^2+ab+ab+b^2=c^2

therefore,

a^+b^2+ab=c^2-ab

Answer 2

Answer:

Hi there!

Step-by-step explanation:

Given :-

→ a + b + c = 0

→ a² + b² + c² = 16

We know that :-

(a + b + c)² = a² + b² + c² + 2(ab + bc + ac)

On substituting th' terms,

0² = 16 + 2(ab + bc + ac)

2(ab + bc + ac) = -16

ab + bc + ac = -16 / 2

ab + bc + ac = -8

Hence, The required answer is :-

ab + bc + ac = -8

                      Hope it helps u!!!!