if a+b+c=0,where a,b,c are non zero real numbers then the value of (a^2-bc)^2-(b^2-ca)(c^2-ab) a)1 b)abc c)a²+b²+c² d)0
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Answer: Using the formula, a^3 + b^3 + c^3 = (a + b + c) (a^2 + b^2 + c^2 ab bc ca) + 3abc
If a+b+c=0,
then a^3 + b^3 + c^3 = 3abc
abc
a
3
+b
3
+c
3
=3
abc
a
3
+
abc
b
3
+
abc
c
3
=3
bc
a
2
+
ca
b
2
+
ab
c
2
=3
Step-by-step explanation:
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