Question

if a+b+c=0and a square +b square+c square=16 then the value of an+bc+ca​

Answer 1

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Answer 2

Answer:

Given :

a + b + c = 0

a² + b² + c² = 16

We Know that,

(a + b + c)² = a² + b² + c² + 2(ab + bc + ca)

putting values that are given in question,

0² = 16 + 2(ab + bc + ca)

-16 = 2(ab + bc + ca)

-16/2 = ab + bc + ca

-8 = ab + bc + ca

So, ab + bc + ca = -8