Question

If a+b+c =11 and
ab+bc+ac=10
find a2+b2+c2​

Answer 1

Answer:

Step-by-step explanation:

(a+b+c)^2=a2+b2+c2+2ab+2bc+2ca

121=a2+b2+c2+2x10

121-20=a2+b2+c2

a2+b2+c2=101

Answer 2

Answer:

101

Step-by-step explanation:

Given that a+B+c= 11

and ab+bc+ac= 10

Therefore, a

${a}^{2} + {b + c}^{2}$

(a+b+c)2- 2(ab+bc+ac)

Replacing the values

(

${11}^{2} - 2 \times 10$

This will give 121-20

Answer= 101

Hope this helped!!