if a+b+c= 12 and a +b+d=64, find the value of ab + bc + ac.
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Step-by-step explanation:
(a+b+c)²=a²+b²+c²+2ab+2bc+2ac=12²
=64+2(ab+bc+ac)=144
=2(ab+bc+ca)=144-64=80
=ab+bc+ca=80/2
=40
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