If a+b+c =12 and ab+bc+ca=47, find the value of a 2 +b 2 +c 2
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Answered by
50
we have formula,
(a +b+c)2 = a2 +b2 +c2+2(ab+bc+ca)
a2 +b2 +c2= 2(ab+bc+ca)-(a +b+c)2
Now substitute the given values in the above equation,
a2 +b2 +c2=2(47)-(12)2
a2 +b2 +c2=94-24
a2 +b2 +c2=70
(a +b+c)2 = a2 +b2 +c2+2(ab+bc+ca)
a2 +b2 +c2= 2(ab+bc+ca)-(a +b+c)2
Now substitute the given values in the above equation,
a2 +b2 +c2=2(47)-(12)2
a2 +b2 +c2=94-24
a2 +b2 +c2=70
Answered by
7
Answer:Answer is 70
Step-by-step explanation:
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