Question

If a+b+c=14,ab+bc+ac=61,find the value of a^2+b^2+c^2

Answer 1

Answer:

-108

Step-by-step explanation:

(a+b+c)^2= a^2 + b^2+c^2+2(ab +bc+ ac)

14=a^2+b^2+ c^2 + 2×61

14 =a^2+b^2+c^2+122

14-122=a^2+b^2+c^2

-108=a^2+b^2+c^2

Answer 2

Answer:

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