Question

if a+b+c = 15 and ab+ bc+ca=60 then find the value of a²+b²+c²?​

Answer 1

Answer:

Answer : 105, explanation given

Answer 2

Given:

$a+b+c=15$

$ab+bc+ca=60$

To Find:

$a^2+b^2+c^2$

Solution:

$a+b+c=15$

$(a+b+c)^2=15^2$

$a^2+b^2+c^2+2ab+2bc+2ca=225$

$a^2+b^2+c^2+2(ab+bc+ca)=225$

$a^2+b^2+c^2+2(60)=225$

$a^2+b^2+c^2+120=225$

$a^2+b^2+c^2=225-120$

$a^2+b^2+c^2=105$

$@rohangupta0424$