Math, asked by Akay28, 1 year ago

If a+b+c=15and a^2+b^2+c^2=83find the value of a^3+b^3+c^3+3abc

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Answered by predators
3

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Answered by xyz8536
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Here is ur answer:

If a+b+c=15 and a^2+b^2+c^2=83,we need to know a,b and c.

Let us try a=3,b=5,c=7,then 3^2+5^2+7^2=9+25+49=83.Correct.

Hence a^3+b^3+c^3-3abc=3^3+5^3+7^3-3*3*5*7=27+125+343-315=180.

ANSWER=180

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