if a+b+c=16 and ab+ bc+ca=3 then find the value a square + b square + c square
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Answer:
a² + b² + c² = 250
Step-by-step explanation:
We will use the following identity over here:
(a + b + c)² = a² + b² + c² + 2(ab + bc + ca)
Substituting the given values
(16)² = a² + b² + c² + 2(3)
256 = a² + b² + c² + 6
a² + b² + c² = 256 - 6 = 250
Hence solved.
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