If a+b+c = 2 p then show that a³+b³+c³+3(2 p-a)(2p-b)(2p-c) = 8p³
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THIS IS A QUESTION OF ALMOST 20-25 POINTS NOT 5
Step-by-step explanation:
The answer turns out to be that a³+b³+c³+3(2 p-a)(2p-b)(2p-c) = 8p³ . This type of problem seems to pop up here frequently, and there is something quite general called the Newton-Girard formulae that can be applied to such problems.
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