If a+b+c=3, abc = (-12) and ab+bc+can = (-4) find the value of a^3+b^3+c^3
Answers
Answered by
0
(a+ b + c) ³= a³+b³+c³+2(ab+bc+ca
Answered by
0
Let a = x and (b +c) = y.
(x + y)³ = x³ + y³ + 3xy ( x + y)
Now substitute the values.
(a + b +c)³ = a³ + (b + c)³ + 3abc (a + b + c)
(a + b + c)³ = a³ + b³ + c³ + 3abc (a + b + c)
Now substitute the values given in the question.
(3)³ = a³ + b³ + c³ + 3 × -12 × -4
27 = a³ + b³ + c³ + 144
a³ + b³ + c³ = 27 - 144
= -117
Ans = -117
Hope it helps! ^^
(x + y)³ = x³ + y³ + 3xy ( x + y)
Now substitute the values.
(a + b +c)³ = a³ + (b + c)³ + 3abc (a + b + c)
(a + b + c)³ = a³ + b³ + c³ + 3abc (a + b + c)
Now substitute the values given in the question.
(3)³ = a³ + b³ + c³ + 3 × -12 × -4
27 = a³ + b³ + c³ + 144
a³ + b³ + c³ = 27 - 144
= -117
Ans = -117
Hope it helps! ^^
Similar questions