Question

If a + b + c = 3abc and (a + b + c) not equal to 0 then-
(a) a+b<c (b) a - b<c (c) b + c<a
(d) a=b=c​

Answer 1

Answer:

We know,

a

3 +b

3 +c

3 −3abc=(a+b+c)(a

2 +b

2 +c

2 −ab−bc−ca)

Putting a+b+c=0 on RHS, we get,

a 3 +b

3 +c 3

−3abc=0

⟹a 3 +b

3 +c 3

=3abc, Hence proved

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