if a+b+c=5,a^+b^+c^=29, then find the value of ab +bc+ca
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Answer:
(a+b+c)^2= a2+b2+c2+2(ab+bc+ca)
(5)^2=29+2(ab+bc+ca)
-4=2(ab+bc+ca)
therefore (ab+bc+ca)= -4/2=-2
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