if a+ b + c = 5 and ab +bc+ac =10 then find the value of a2+b2+c2
Answers
Answered by
16
Answer:
15
Step-by-step explanation:
(a+b+c)²=a²+b²+c²+2ab+2bc+2ac
(5)²=a²+b²+c²+2(ab+bc+ac)
25=a²+b²+c+2(10)
a²+b²+c²=25-10
a²+b²+c²=15
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Answered by
13
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Answer:
a^2+b^2+c^2=5
Step-by-step explanation:
by using identity V,
(x+y+z)^2=x^2+y^2+z^2+2xy+2yz+2zx
∴(a+b+c)^2=a^2+b^2+c^2+2ab+2bc+2ca
⇒a^2+b^2+c^2=(a+b+c)^2-2ab-2bc-2ca
=(5)^2 -2(ab+bc+ca)
=25-2(10)
=25-20
=5
∴The value of a^2+b^2+c^2=5
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