if a+b+c=6 and a square + b square + c square = 14 then find the value of ab + bc + ca
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3
Answer:
ab+bc+ca=>22+22+22=>66
Answered by
4
Step-by-step explanation:
(a+b+c)²=a²+b²+c²+2(ab+bc+ac)
2(ab+bc+ac)=(a+b+c)²-(a²+b²+c²)
2(ab+bc+ac)=(6)²-(14)
2(ab+bc+ac)=36-14
2(ab+bc+ac)=22
ab+bc+ac=11
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