Question

if a+b+c =6 and a²+b²+c²=20, find ab+bc+ca​

Answer 1

Answer:

(a+b+c)² = a²+b²+c²+ 2ab + 2bc + 2ca

6² = 20 + 2ab + 2bc + 2ca

36 -20 = 2(ab+bc+ca)

16/2 = ab + bc + ca

ab + bc+ca = 8

Step-by-step explanation:

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Answer 2

Answer:

okay mate !

a+b+c=6, a²+b²+c²=20 ther fore ab+bc+ca = ?

Step-by-step explanation:

(a+b+c)² = a²+b²+c²+ 2ab + 2bc +2ca

putting the values :-

(6)² = (20) + 2(ab + bc+ca)

---------------- (taking "2" as common from the equation in bracket)

36 = 20 + 2(ab + bc + ca)

36 - 20 = 2(ab + bc + ca)

16 = 2(ab + bc + ca)

16/2 = ab + bc + ca

8 = ab + bc + ca

hope this will help

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