Question

If a+b+c=6 ; bc+ca+ab=11 ; abc=6, then the value of (1-a)(1-b)(1-c) is​

Answer 1

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$(1-a)(1-b)(1-c)= (1-b-a+ab) (1-c)$

$= 1-b-a+ab-c+bc+ac-abc$

$=1-(a+b+C) +(ab+bc+ac)-(abc)$

$=1-6+11-6$

$=12-12$

$=0 \: \: \: \: \: answer \:$

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