Math, asked by sutapachowdhury1978, 1 year ago

if (a+b+c)=8 and (ab+bc+ca)=18 find a^2+b^2+c^2​

Answers

Answered by ineerajrajeev
3

Answer:

28

Step-by-step explanation:

 {(x + y + z)}^{2}  =  {x}^{2}  +  {y}^{2}  +  {z}^{2}  + 2(xy + yz + zx)

substituting values

 {8}^{2}  =  {x}^{2}  +  {y}^{2}  +  {z}^{2}  + 2(18)

simplifying the equation

 {x}^{2}  +  {y}^{2}  +  {z}^{2}  = 28

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