If a+b+c=9
ab+bc+ca=26
find a^2+b^2+c^2
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(a+b+c)^2=a^2+b^2+c^2 +2(ab+bc+ac)
9^2=a^2+b^2+c^2+(2×26)
81=a^2+b^2+c^2+52
a^2+b^2+c^2=81-52=29
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9^2=a^2+b^2+c^2+(2×26)
81=a^2+b^2+c^2+52
a^2+b^2+c^2=81-52=29
If you like the answer please mark me as brainliest and follow me
yogendra1024:
plz mark me as brainliest
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Answer:
Step-by-step explanation:
(a+b+c)^2=a^2+b^2+c^2 +2(ab+bc+ac)
9^2=a^2+b^2+c^2+(2×26)
81=a^2+b^2+c^2+52
a^2+b^2+c^2=81-52=29
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