Question

If a+b+c =9, ab +bc +ca = 26 find the value of a² +b²+b²+c²
Plz help me.....

Answer 1

Answer:

a² + b² + c² + 2(ab + bc + ca)

= (a+b+c)²

a² + b² + c² + 2*26 = (9)²

a² + b² + c² + 52 = 81

a² + b² + c² = 81 - 52 = 29

Hence, your answer is 29.

HOPES IT HELPS!

Answer 2

Answer:

29

Step-by-step explanation:

By identity :-

${(a + b + c)}^{2} = {a + }^{2} {b}^{2} + {c}^{2} + 2(ab + bc + ca)$

Putting the value , we get :-

81= a^2+b^2+c^2 +52

a^2+b^2+c^2 = 81-52 = 29 (Answer )