if a+b+c=9 ab+bc+ca=26 then find a^2+b^2+c^2
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0
Answer:
133
Step-by-step explanation:
using identity
a²+b²+c²=(a+b+c)²=a²+b²+c²+2(ab+bc+ca)
so,
putting values
9²+2(26)
81+52
=133
hope it helps :)
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