If (a+b+c)=9(ab+BC+CA)=5 find (a^2+ b^2c^2)
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Step-by-step explanation:
Given, a+b+c=9 and ab+bc+ca=26.
We know, (a+b+c)
2 =a 2 +b 2 +c 2+2ab+2bc+2ca
⇒(a+b+c) 2
=a 2 +b 2 +c 2 +2(ab+bc+ca).
putting the values here, we get(9) 2 =a 2 +b 2 +2(26)
⇒81=a
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