If a+b+c = 9, ab +bc+can =26, find the value of a² +b²+b²+c².
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Answer:
Step-by-step explanation:
→ (a+b+c)² = a² + b² + c² + 2(ab+bc+ca)
→ Given:
→ a+b+c = 9 & ab+bc+ca = 26
→ Now putting the values in the above formula,
→ We get,
→ (9)² = a² + b² + c² + 2×26
→ 81 = (a² +b² +c²) + 52
→ (a² +b²+c²) = 81-52
→ (a² + b² + c²) = 29
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