If a+b+c=9 and a^2+b^2+c^2=35 Then the value of a^3+b^3+c^3-3abc=
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Step-by-step explanation:
(a+b+c)^2= a^2+b^2+c^+2(ab+bc+ca)
81=35+2(ab+bc+ca)
-ab-bc-ca=81-35=46/2=23
(a+b+c)(a^2+b^2+c^2-ab-bc-ca)=9(35-23)= 12×9=108
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