Math, asked by Sevyasahasra, 9 months ago

If a+b+c=9 and a^2+b^2+c^2=35 Then the value of a^3+b^3+c^3-3abc=​

Answers

Answered by jyotirmayee2233
1

Answer:

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Answered by tanisk76
0

Step-by-step explanation:

(a+b+c)^2= a^2+b^2+c^+2(ab+bc+ca)

81=35+2(ab+bc+ca)

-ab-bc-ca=81-35=46/2=23

(a+b+c)(a^2+b^2+c^2-ab-bc-ca)=9(35-23)= 12×9=108

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