if a+b+c=9 and a2+b2+c2=29,find the value of a3+b3+c3-3abc
shashank2895:
13.5
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Answered by
10
Answer:
Hey mate!
Here is your answer..
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This answer is wrong
yup
27
is correct
I know
Ok
I have solved it bt it is not posting sm error
answer is wrong
Answered by
13
Answer:
(a+b+c)2=a2+b2+c2+2ab+2bc+2ca
(9)^2=29+2(ab+bc+ca)
81-29=2(ab+bc+ca)
52÷2=ab+bc+ca
26=ab+bc+c
a3+b3+c3-3abc=(a+b+c)(a2+b2+c2-ab+bc-ca)
=(9)(29-26)
=9(3)
=27. ans
Step-by-step explanation:
i think this is correct answer
thanks
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