Math, asked by ananta892005, 11 months ago

If a+b+c = 9 and a2 +b2 +c2 =35 find the value of a3 +b3 +c3 – 3abc. ​

Answers

Answered by navjot9440
8

Answer:

(a².a) +(b².b)+(c².c)

Step-by-step explanation:

put the value

Answered by TheBossHere
31

Answer:

answer is 108. plspls mark brainliest

Step-by-step explanation:

a2+b2+c2=(a+b+c)2-2(ab+bc+ca)

35=81-2(ab+bc+ca)

2(ab+bc+ca)=46.

(ab+bc+ca)=23

a3+b3+c3-3abc

=(a+b+c)(a2+b2+c2-(ab+bc+ca))

substituting values,

a3+b3+c3-3abc=9×(35-23)=9×12=108.

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