if a+_b+c=9 and ab+bc+ca=23 , then find a^2+b^2+c^2
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(a+b+c)²=a²+b²+c²+2ab+2bc+2ca
(a+b+c)=9
ab+bc+ca=23
(a+b+c)²=a²+b²+c²+2(ab+bc+ca)
(9)²=a²+b²+c²+2(23)
81-46=a²+b²+c²
35=a²+b²+c²
(a+b+c)=9
ab+bc+ca=23
(a+b+c)²=a²+b²+c²+2(ab+bc+ca)
(9)²=a²+b²+c²+2(23)
81-46=a²+b²+c²
35=a²+b²+c²
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