If a+b+c=9 and ab + bc + ca =26; find a^2 +b^2+c^2?
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a+b+c=9
Squaring on both sides
(a+b+c)²=9²
a²+b²+c²+2(ab+bc+ca)=81
a²+b²+c²+2(26)=81
a²+b²+c²=81-52
a²+b²+c² = 29
Squaring on both sides
(a+b+c)²=9²
a²+b²+c²+2(ab+bc+ca)=81
a²+b²+c²+2(26)=81
a²+b²+c²=81-52
a²+b²+c² = 29
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