Question

if a+b+c=9 and ab+bc+ca=26, find a^2+b^2+c^2.
[answer:, -1,2,-3 sent by teacher]


find the zeros of (x-y)^2-(x+y)^2
[answer: a=5, b=8 sent by teacher]


please help with the above questions!

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Answer 1

Answer:

a^2+b^2+c^2=61

Step-by-step explanation:

(a+b+c)^2=a+b+c+2(ab+bc+ca)

(a+b+c)^2=9+2(26)

(a+b+c)^2=9+52

(a+b+c)^2=61

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Sorry but i dont know the answer of the question number 2