If a + b + c = 9 and ab + bc + ca = 40, find a² + b² + c².
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Answered by
3
(a+b+c)^2 = a^2 +b^2 +c^2 +2(ab+bc+ca)
a^2 +b^2 +c^2 =(9)^2-2(40)
=81-80=1
Answered by
5
Answer:
Step-by-step explanation:
Given a +b+c =9
ab + bc + ca= 40
(a+b+c+)^2= a^2 + b^2 +c^2+2ab+2bc+2ca
= (a+b+c)^2-2(ab +bc +ca)
=9^2 - 2×40
=81-80
= 1 ans
Hope it will help
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