If a+b-c/a+b=b+c-a/b+c=c+a-b/c+a and a+b+c not=0 then prove that a=b=c
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Answered by
20
a+b-c/a+b = -c(a+b/a+b=0)
b+c-a/b+c = -a
c+a-b/c+a = -b
so -c = -a = -b
therefore, a=b=c
b+c-a/b+c = -a
c+a-b/c+a = -b
so -c = -a = -b
therefore, a=b=c
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Answered by
21
Answer:
Step-by-step explanation:
a+b-c/a+b = -c(a+b/a+b=0)
b+c-a/b+c = -a
c+a-b/c+a = -b
so -c = -a = -b
therefore, a=b=c
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