Question

If A + B + C = π & cosA = cosB. cosC then tanB. tanC has the value equal to? ​

Answer 1

Answer:

→ 2.

Step-by-step explanation:

For solution :

See the attachment.

Hence, it is solved.

Answer 2

$\mathfrak{\huge{\blue{\underline{\underline{AnswEr :}}}}}$

⚘ A + B + C = π

⇒A = π - (B + C)

Multiply Cos to both Sides:

⇒CosA = Cosπ - Cos(B + C)

⇒CosA = 0 - Cos(B + C) --[Cosπ = 0]

⇒CosA = - CosB.CosC + SinB.SinC

⇒CosB.CosC = - CosB.CosC + SinB.SinC

--[CosA = CosB.CosC]

⇒CosB.CosC + CosB.CosC = SinB.SinC

⇒2CosB.CosC = SinB.SinC

⇒SinB.SinC/CosB.CosC = 2

⇒TanB.TanC = 2

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