Question

If a+b+c and ab+bc+ca =26,find a^2+b^2+c^2 ​

Answer 1

Answer:

In this identity will use that is, (a+b+c)²=a²+b²+c²+2(ab+bc+ca)

9²=a²+b²+c²+2(26)

81=a²+b²+c²+52

a²+b²+c²=81-52

a²+b²+c²=29

Step-by-step explanation:

Answer 2

Step-by-step explanation:

(a+b+c)^2=a^2+b^2+c^2+ab+bc+ca

26^2=a^2+b^2+c^2+26

676-26=a^2+b^2+c^2

650=a^2+b^2+c^2

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