If a, b, c and d are four odd perfect cube numbers, then which of the following is always a factor of (3under root a + 3under root b) whole square , (3under root c + 3under root d)?
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Answered by
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(∛a + ∛b)² (∛c + ∛d)
2) 8
let us check imagine 4 odd cubic numbers as 1, 3, 5, 7
(1 + 3)² (5 + 7) = 16 x 12 (8 comes as factor)
(1+5)² (3 +7) = 36 x 10 (8comes as factor)
(1+7)² (3+5) = 64 x 8 (8 comes as factor)
Answered by
2
Thank you for asking this question. Here is your answer:
a = 1
b = 8
c = 125
d = 343
These are the four odd perfect cube numbers.
∛a=∛1=1,∛b=∛8=2,∛c=∛125=5 and ∛d=∛343=7
(∛a+∛b)^2 (∛c ∛d) will be 192, 360, 512, 576 and 600
(192, 360, 512, 576, 600) = 8
So this means that 8 will always be the factor of (∛a+∛b)^2 (∛c+∛d)
If there is any confusion please leave a comment below.
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