Question

if a,b,c,and d are four odd perfect cube numbers, then which of the following is always a factor of (cuberoot of a+cuberoot of b) square+(cuberoot of c+ cuberoot of d)?

Answer 1

if a,b,c,d are odd perfect cube no's.

then cube root of a,cube root of b,cube root of c,cube root of d are also odd

so cube root of a + cube root of b = even

so (cube root of a+ cube root of b has factor 2

(cube root of a+ cube root of b)^2 has factor 4

cube root of c+ cube root of d has factor 2

In question there should not be addition sign which u have put by mistake

So 4×2 = 8 as factor

NOTE: if addition sign then 2 will be factor