If A, B, C
angles of a triangle such that
A is obtuse, then tanB. tanC=
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Step-by-step explanation:
A is obtuse angle.
Then
2
π
<A<π
⇒
2
π
<π−(B+C)<π
⇒−
2
π
>−π+(B+C)>−π
⇒
2
π
>(B+C)>0
∵B+C<
2
π
⇒B<
2
π
−C
⇒tanB<tan(
2
π
−C)
⇒tanB<cotC
∴tanB<
tanC
1
Hence tanBtanC<1
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