Question

if A,B,C are acute angles ,tanA=1/2 tanB=1/5,tanC=1/8 then A+B+C=​

Answer 1

Hola mate..

tan(a + b)

= [tan(a) + tan(b)] / [1 - tan(a)tan(b)]

= [(1/3) + (1/7)] / [1 - (1/3)(1/7)]

= (7 + 3) / (21 - 1)

= 1/2

tan(c + d)

= [tan(c) + tan(d)] / [1 - tan(c)tan(d)]

= [(1/5) + (1/8)] / [1 - (1/5)(1/8)]

= (8 + 5) / (40 - 1)

= 1/3

tan(a + b + c + d)

= [tan(a + b) + tan(c + d)] / [1 - tan(a + b)tan(c + d)]

= [(1/2) + (1/3)] / [1 - (1/2)(1/3)]

= (3 + 2) / (6 - 1)

= 1

If the four given angles are all acute -- and you should have included that condition -- then the sum of the angles is π/4

Hope this helps u dude ✌

If helpful Mark it as Brainliest answer ❤️☺️

Answer 2

1divide by 2

$1 \div 2 + 1 \div 8 \div 1 \div 5$

lcm is 20 +20+20=60