If A, B, C are adjacent angles and triangle ABC then show that ( B + C / 2) = Cas A/ 2
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Step-by-step explanation:
We know that the sum of angles of a triangle = 180.
- A + B = 180
- B + C = 180
- B +C = 180-A
- B +C/2= 180-A/2
- B +C = 90-A/2
- sin (B+C /2) = sin (90 - A/2)
- sin (B+C)= cos A/2
Hence, sin (B+C )= cos A/2
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