Math, asked by mastershivam11022006, 9 months ago

if a,b,c are all non zero and a+b+c=0 , prove that a²/bc+b²/ca+c²/ab=3​

Answers

Answered by himanshisahu0620
1

Step-by-step explanation:

given a+b+c =0

and we know that when a+b+c=0

then a^3+b^3+c^3 = 3abc. .....(1)

solving LHS,

a^2/bc + b^2/ac + c^2/ab

= (a^3 + b^3 + c^3)/abc

= 3abc/abc from eqn 1

= 3 RHS

Answered by sandy1816
2

Answer:

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