if a,b,c are all non zero and a+b+c=0 , prove that a²/bc+b²/ca+c²/ab=3
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Step-by-step explanation:
given a+b+c =0
and we know that when a+b+c=0
then a^3+b^3+c^3 = 3abc. .....(1)
solving LHS,
a^2/bc + b^2/ac + c^2/ab
= (a^3 + b^3 + c^3)/abc
= 3abc/abc from eqn 1
= 3 RHS
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