If a,b,c are all non-zero and a+b+c=0, prove that
plzzzz solve .....step by step...
roushan12:
hiii
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Answered by
1
take t to the left your equation will look like
a+b=-c
cube both side
a3+b3+3a2b+3ab2=-c3
now divide it by abc
a+b=-c
cube both side
a3+b3+3a2b+3ab2=-c3
now divide it by abc
who kya
okkk Don't text here...
when a+b+c=0 then a^3+b^3+c^3=3abc a^2/bc +b^2/ca +c^2/ab=(a^3+b^3+c^3)/abc=3abc/abc=3
okk
thanks one more time
prove how is a3 b3 c3 =3abc
are u understand
noo
a^3+b^3+c^3-3abc=(a+b+c)(a^2+b^2+c^2-ab-bc-ca) given that a+b+c=0 then a^3+b^3+c^3-3abc=0 a^3+b^3+c^3=3abc
r u. understand
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HOPE IT HELPS..........THANK YOU.
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