Question

If a,b,c are distinct and if deteminant |a a*a a*a*a-1| |b b*b b*b*b-1|=0 |c c*c c*c*c-1| then prove that a*b*c =1

Answer 1

Answer:

aa*a*a*a*b*b*b*bzcaaaaaaaaaaa

Answer 2

Answer:

9

Step-by-step explanation:

Hello friend!

Zero of the polynomial is -4

p(x)=x²-x-(2k+2)

p(x)=x²-x-2k-2

p(-4)=0

0=-4²-(-4)-2k-2

0=16+4-2k-2

0=18-2k

2k=18

k=18/2=9

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