If a,b,c are in A.P. and a,b,(c+1) are in G.P, show that : a=(a-b)²
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If a,b,c are in A.P and a,x,b and b,y,c are in G.P , show that x
2
,b
2
,y
2
are in A.P.
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Solution
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We have,
a,b,c are in A.P.
2b=a+c ……. (1)
a,x,b are in G.P.
x
2
=ab …… (2)
b,y,c are in G.P.
y
2
=bc ……. (3)
From equation (1) and (2), we get
x
2
=(2b−c)b
x
2
=2b
2
−bc
On putting the value of bc in above expression, we get
x
2
=2b
2
−y
2
2b
2
=x
2
+y
2
So, x
2
,b
2
,y
2
are in A.P.
Hence, proved.
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