Insert 3 geometric mean between9/1 and 9
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Answer:
Let G1, G2 and G3 be the three geometric means. Thus 1, G1, G2, G3, 9 is the required G.P
a = 1,
a
r
4
=
9
∴
1
×
r
4
=
9
or
(
r
2
)
2
=
(
3
)
2
⇒
r
=
√
3
G
1
=
a
r
=
1
×
√
3
=
√
3
G
2
=
a
r
2
=
1
×
(
√
3
)
2
=
3
G
3
=
a
r
3
=
1
×
(
√
3
)
2
.
√
3
=
3
√
3
∴
The 3 G.Ms are
√
3
,
3
,
3
√
3
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